x=x^2-10x+25

Solution for x=x^2-10x+25 equation:

x=x^2-10x+25

We move all terms to the left:

x-(x^2-10x+25)=0

We get rid of parentheses

-x^2+x+10x-25=0

We add all the numbers together, and all the variables

-1x^2+11x-25=0

a = -1; b = 11; c = -25;
Δ = b2-4ac
Δ = 112-4·(-1)·(-25)
Δ = 21
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{21}}{2*-1}=\frac{-11-\sqrt{21}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{21}}{2*-1}=\frac{-11+\sqrt{21}}{-2}
$